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Question regarding result interpretation of RatcliffObershelpSimilarity #2

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@OevreFlataeker

Just for my clarification: A comparison of two identical strings should always yield a 1.0 as result, correct?

string s1 = "hello world";
string s2 = "hello world";
double x = s1.RatcliffObershelpSimilarity(s2);
-> x = 0.7272727272

Also, I was trying to get the same numbers like on this page for reference checking: https://itnext.io/string-similarity-the-basic-know-your-algorithms-guide-3de3d7346227

But already the first example differs:

string1, string2 = "i am going home", "gone home"
textdistance.ratcliff_obershelp(string1, string2)
0.66

Your extension: 0.58333333

string1, string2 = "test", "text"
textdistance.ratcliff_obershelp(string1, string2)
0.75

Your extension: 0.5

Am I using the extension wrong or is there a problem with the implementation?

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