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added a parsons problem for section 3.5 #387

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added a parsons problem for section 3.5 #387

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42 changes: 42 additions & 0 deletions source/ch3_javadatatypes.ptx
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Original file line number Diff line number Diff line change
Expand Up @@ -967,6 +967,48 @@ public class HistoArray {
<p>
The main difference between <xref ref="java-array" text="type-global"/> and <xref ref="java-histogram" text="type-global"/> is that we declare <c>count</c> to be an <c>Array</c> of integers. We also can initialize short arrays directly using the syntax shown here: <c>Integer[] count = {0,0,0,0,0,0,0,0,0,0}</c>Then notice that we can use the square bracket notation <c>count[idx]</c> to index into an array.
</p>

<exercise xml:id="java-arrays-parsons-exercise" label="java-arrays-parsons">
<statement>
<p>
Construct a short Java program that creates an array of three integers,
changes the first value, and prints it. Drag the blocks into the correct order on the right.
</p>
</statement>
<blocks>
<block order="1">
<cline>public class ArrayExample {</cline>
<cline> public static void main(String[] args) {</cline>
</block>

<block order="2">
<choice correct="yes">
<cline> Integer[] nums = {1, 2, 3};</cline>
</choice>
<choice correct="no">
<cline> Integer[] nums = (1, 2, 3);</cline>
</choice>
</block>

<block order="3">
<choice correct="yes">
<cline> nums[0] = 5;</cline>
</choice>
<choice correct="no">
<cline> nums(0) = 5;</cline>
</choice>
</block>

<block order="4">
<cline> System.out.println(nums[0]);</cline>
</block>

<block order="5">
<cline> }</cline>
<cline>}</cline>
</block>
</blocks>
</exercise>
</section>

<section xml:id="dictionary">
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